Derivations and the first Hochschild cohomology group of the quantum grassmannian

  • Stéphane Launois

    Université Caen Normandie, France
  • Thomas H. Lenagan

    The University of Edinburgh, UK
Derivations and the first Hochschild cohomology group of the quantum grassmannian cover
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Abstract

We calculate the derivations and the first Hochschild cohomology group of the quantum grassmannian over a field of characteristic zero in the generic case when the deformation parameter is not a root of unity. Using graded techniques and two special homogeneous normal elements of the quantum grassmannian, we reduce the problem to computing derivations of the quantum grassmannian that act trivially on these two normal elements. We then use the dehomogenisation equality which shows that a localisation of the quantum grassmannian is equal to a skew Laurent extension of quantum matrices. This equality is used to connect derivations of the quantum grassmannian with those of quantum matrices. More precisely, again using graded techniques, we show that derivations of the quantum grassmannian that act trivially on our two normal elements restrict to homogeneous derivations of quantum matrices. The derivations of quantum matrices are known in the square case, and technical details needed to deal with the general case are given in the appendix. This allows us to explicitly describe the first Hochschild cohomology group of the quantum grassmannian.

1. Introduction

Let K denote a field of characteristic zero and qK be a nonzero element which is not a root of unity. The quantum grassmannian 𝒪q(G(k,n)) is a noncommutative algebra that is a deformation of the homogeneous coordinate ring of the classical grassmannian of k-planes in n-space. In this paper, we calculate the derivations and the first Hochschild cohomology group of the quantum grassmannian.
One of the motivations for this paper is [7
M. Movshev and A. Schwarz, Quantum deformation of planar amplitudes. J. High Energy Phys. 2018 (2018), no. 4, article no. 121, 19 pp. Zbl 1390.81613 MR 3801153
] where a connection between the totally nonnegative grassmannian – or rather its cell decomposition into the union of so-called positroid cells – and Hochschild (co)homology of 𝒪q(G(k,n)) was established. More precisely, a link between the volume form of positroids and Hochschild (co)homology of the quantum grassmannian 𝒪q(G(k,n)) is established, allowing the contribution of a positroid cell to the scattering amplitude (in the N=4 supersymmetric Yang–Mills theory) to be q-deformed. The present paper is the first one in a project to compute the Hochschild (co)homology of quantum positroid varieties. More precisely, the quantum grassmannian can be viewed as a “quantum positroid variety” (corresponding to the totally positive grassmannian) thanks to [5
S. Launois, T. H. Lenagan, and B. M. Nolan, Total positivity is a quantum phenomenon: the grassmannian case. Mem. Amer. Math. Soc. 291 (2023), no. 1448, 109 pp. Zbl 1548.16002 MR 4665212
], and we compute the first Hochschild cohomology group of the quantum grassmannian. We will come back to the general case in future work.
Assume kn. Recall that 𝒪q(G(k,n)) is the subalgebra of the quantum matrix algebra 𝒪q(M(k,n)) that is generated by the k×k quantum minors of 𝒪q(M(k,n)). We call these k×k quantum minors quantum Plücker coordinates of 𝒪q(G(k,n)). They are indexed by k-subsets of {1,,n} and denoted by [I] for each k-subset I. The algebra 𝒪q(G(k,n)) is graded with all quantum Plücker coordinates homogeneous of degree one.
Quantum Plücker coordinates formed on consecutive columns play a special role: they are normal, and each one generates a completely prime ideal of 𝒪q(G(k,n)). They are referred to as prime quantum Plücker coordinates. Among the prime quantum Plücker coordinates, two are special: [u]=[1,,k] and [w]=[nk+1,,n]. The reason for this is that [u] (respectively, [w]) q-commutes with every quantum Plücker coordinate [I] with a nonnegative (respectively, nonpositive) power of q, that is,
[u][I]=q0[I][u]and[w][I]=q0[I][w].
We exploit this observation and other graded techniques in order to reduce the problem of computing derivations of 𝒪q(G(k,n)) to computing derivations D of 𝒪q(G(k,n)) that act trivially on both [u] and [w], that is, derivations D such that D([u])=D([w])=0.
We then employ the dehomogenisation equality which shows that a localisation of the quantum grassmannian is equal to a skew Laurent extension of quantum matrices. This equality is used to connect the set of derivations of the quantum grassmannian acting trivially on [u] and [w] with that of quantum matrices. More precisely, again using graded techniques, we show that derivations of the quantum grassmannian that act trivially on [u] and [w] restrict to homogeneous derivations of quantum matrices. To conclude, we use our knowledge of derivations of quantum matrices: the set of derivations is known in the case of square quantum matrices; see [3
S. Launois and T. H. Lenagan, The first Hochschild cohomology group of quantum matrices and the quantum special linear group. J. Noncommut. Geom. 1 (2007), no. 3, 281309 Zbl 1137.16015 MR 2314098
]. Some technical details that are needed to deal with the fact that the non-square case has not yet been covered are given in the appendix.
This allows us to show that the first Hochschild cohomology group of 𝒪q(G(k,n)) is a K-vector space of dimension n, with basis given by the cosets of the derivations D1,,Dn, where Di is the derivation of 𝒪q(G(k,n)) defined by
Di([I])={[I] if iI;0 otherwise.

2. Basic definitions

Throughout the paper, K denotes a field of characteristic zero and qK is a nonzero element which is not a root of unity.
The algebra of m×n quantum matrices over K, denoted by 𝒪q(M(m,n)), is the algebra generated over K by mn indeterminates xij, with 1im and 1jn, which commute with the elements of K and are subject to the relations
xijxil =qxilxij for 1im and 1j<ln; xijxkj =qxkjxij for 1i<km and 1jn; xijxkl =xklxij for 1k<im and 1j<ln; xijxklxklxij =(qq1)xilxkj for 1i<km and 1j<ln.
It is well known that 𝒪q(M(m,n)) is an iterated Ore extension over K with the xij added in lexicographic order. An immediate consequence is that 𝒪q(M(m,n)) is a noetherian domain.
When m=n, the quantum determinant Dq is defined by
Dq:=(q)l(σ)x1σ(1)xnσ(n),
where the sum is over all permutations σ of {1,,n} and where l(σ) denotes the length of the permutation σ.
The quantum determinant is a central element in the algebra of quantum matrices 𝒪q(M(n,n)).
If I and J are t-element subsets of {1,,m} and {1,,n}, respectively, then the quantum minor [I|J] is defined to be the quantum determinant of the t×t quantum matrix subalgebra generated by the variables xij with iI and jJ.
The quantum matrix algebra 𝒪q(M(m,n)) is a connected -graded algebra with each generator xij given degree one. Note that each t×t quantum minor has degree t.

Definition 2.1.

Let kn. The homogeneous coordinate ring of the k×n quantum grassmannian, 𝒪q(G(k,n)) (known informally as the quantum grassmannian), is the subalgebra of the quantum matrix algebra 𝒪q(M(k,n)) that is generated by the k×k quantum minors of 𝒪q(M(k,n)); see, for example, [2
A. C. Kelly, T. H. Lenagan, and L. Rigal, Ring theoretic properties of quantum grassmannians. J. Algebra Appl. 3 (2004), 930 Zbl 1081.16048 MR 2047633
].
A k×k quantum minor of 𝒪q(M(k,n)) must use all of the k rows, and so we can specify the quantum minor by specifying the columns that define it. With this in mind, we will write [J] for the quantum minor [1,,k|J] for any k-element subset J of {1,,n}. Quantum minors of this type are called quantum Plücker coordinates. The quantum grassmannian 𝒪q(G(k,n)) is a connected -graded algebra with each quantum Plücker coordinate given degree one. The set of quantum Plücker coordinates in 𝒪q(G(k,n)) is denoted by Π. There is a natural partial order on Π defined in the following way: if I=[i1<<ik] and J=[j1<<jk], then [I]<[J] if and only if iljl for each l=1,,k. A standard monomial in the quantum Plücker coordinates is an expression of the form [I1][I2][It], where I1I2It in this partial order. The set of all standard monomials forms a vector space basis of 𝒪q(G(k,n)) over K; see, for example, [2
A. C. Kelly, T. H. Lenagan, and L. Rigal, Ring theoretic properties of quantum grassmannians. J. Algebra Appl. 3 (2004), 930 Zbl 1081.16048 MR 2047633
, Corollary 2.1]. We will refer to the process of rewriting a monomial in terms of standard monomials as straightening.
The quantum grassmannian 𝒪q(G(1,n)) is a quantum affine space, and, as such, its derivations are known; see [1
J. Alev and M. Chamarie, Dérivations et automorphismes de quelques algèbres quantiques. Comm. Algebra 20 (1992), no. 6, 17871802 Zbl 0760.17003 MR 1162608
, Corollaire 1.3.3]; so we will assume throughout this paper that k>1. As 𝒪q(G(n1,n))𝒪q(G(1,n)), by [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Proposition 3.4], we exclude the case k=n1 as well. Thus, we will assume throughout the paper that 2kn2, and so n4.
Also, it is shown in [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Proposition 3.4] that 𝒪q(G(k,n))𝒪q(G(nk,n)), when 2kn. In Section 7, we need to assume that 2kn, and the general result is obtained from this case in Subsection 8.2 by using the isomorphism just mentioned.

3. Derivations for 𝒪q(G(k,n)) inherited from 𝒪q(M(k,n))

We use the following notation for the delta truth function: if P is a proposition, then δ(P)=1 if P is true, and δ(P)=0 if P is false. As is traditional, we write δij for δ(i=j).
Recall from [3
S. Launois and T. H. Lenagan, The first Hochschild cohomology group of quantum matrices and the quantum special linear group. J. Noncommut. Geom. 1 (2007), no. 3, 281309 Zbl 1137.16015 MR 2314098
] that for each column of 𝒪q(M(k,n)) there is a derivation that is the identity on any quantum minor that contains that column and is zero on the other quantum minors. These derivations restrict to the subalgebra 𝒪q(G(k,n)) to give us n derivations which we denote by Di for i=1,,n. We refer to these derivations as the column derivations of 𝒪q(G(k,n)).

Lemma 3.1.

For each i=1,,n, there is a derivation Di whose action on quantum Plücker coordinates is given by Di([I])=δ(iI)[I].

Proof.

This is immediate from the definition of Di as the restriction to 𝒪q(G(k,n)) of a column derivation of 𝒪q(M(k,n)).  

Corollary 3.2.

We have
1k(i=1nDi)([I])=[I]
for each quantum Plücker coordinate [I] in 𝒪q(G(k,n)).

Proof.

This follows immediately from the previous lemma, as there are k occurrences of Di for which Di([I])=[I], and otherwise Di([I])=0.  
Our main aim in this paper is to prove the following conjecture.

Conjecture 3.3.

Let K be a field of characteristic zero, and let q be a nonzero element of K that is not a root of unity. Then every derivation of 𝒪q(G(k,n)) can be written as a linear combination of inner derivations and column derivations. Furthermore, the column derivations are linearly independent modulo the space generated by the inner derivations.
As a consequence of the truth of this conjecture, we identify the first Hochschild cohomology group of the quantum grassmannian.

4. The dehomogenisation equality for 𝒪q(G(k,n))

In this section, we recall results concerning the dehomogenisation equality that occur in [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Section 3]. We refer the reader to that paper for detailed definitions and proofs.
Set u={1,,k}. Then [u] commutes with all other quantum Plücker coordinates up to a power of q, by [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Lemma 3.1]. As 𝒪q(G(k,n)) is generated by the quantum Plücker coordinates, it follows that the element [u] is a normal element, and so we may invert [u] to obtain the overring T:=𝒪q(G(k,n))[[u]1].
For 1ik and 1jnk, set
xij:=[1,,k+1i^,,k,j+k][u]1T.
Set p:=nk. The elements xij generate a subalgebra of T that is a quantum matrix algebra 𝒪q(M(k,p)). In fact, T is generated over 𝒪q(M(k,p)) by [u]±1, so
T=𝒪q(G(k,n))[[u]1]=𝒪q(M(k,p))[[u]±1;σ],
where σ is the automorphism of 𝒪q(M(k,p)) defined by σ(xij):=qxij (since [u]xij=qxij[u] for all i,j).
When we operate on the right-hand side of this equality, we will write y for [u]. Thus, yxij=σ(xij)y and
(4.1)
T=𝒪q(G(k,n))[[u]1]=𝒪q(M(k,p))[y,y1;σ].
We refer to this equality as the dehomogenisation equality. We will make extensive use of the dehomogenisation equality to transfer derivations from 𝒪q(M(k,p)) to 𝒪q(G(k,n)) and vice versa.
Note that [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Lemma 3.2] gives the formula for general quantum minors of the algebra 𝒪q(M(k,p)) when viewed as elements in 𝒪q(G(k,n))[[u]1], and each quantum Plücker coordinate, multiplied by [u]1, occurs in the formula. The formula is
[I|J]=[{1,,k}\(k+1I)(k+J)][u]1.
In the reverse direction, for a quantum Plücker coordinate [L] of 𝒪q(G(k,n)), we have
[L]=[LkL>k]=[I|J][u],
where I={(k+1)({1,,k}\Lk)} and J=L>kk with Lk:=L{1,,k} and L>k:=L{k+1,,n}.

5. Derivations arising via dehomogenisation

The n column derivations Di of 𝒪q(G(k,n)) that we have defined in Section 3 satisfy Di([u])=[u] for 1ik and Di([u])=0 for k<in, so they extend to n derivations Di~ of T=R[y,y1;σ]=𝒪q(G(k,n))[u]1 with Di~(y)=y for 1ik and Di~(y)=0 for k<in.
We will show that these derivations Di~ of T coincide with extensions of known derivations of 𝒪q(M(k,p)) which we now recall from [3
S. Launois and T. H. Lenagan, The first Hochschild cohomology group of quantum matrices and the quantum special linear group. J. Noncommut. Geom. 1 (2007), no. 3, 281309 Zbl 1137.16015 MR 2314098
].
For 1ik, there are derivations Di of 𝒪q(M(k,p)) defined by Di(xrs):=δirxrs, and for 1jp, there are derivations Dj of 𝒪q(M(k,p)) defined by Dj(xrs):=δjsxrs. In other words, Di fixes row i and kills all the other rows of 𝒪q(M(k,p)), while Dj fixes column j and kills all other columns of 𝒪q(M(k,p)). For these observations, see the comment after [3
S. Launois and T. H. Lenagan, The first Hochschild cohomology group of quantum matrices and the quantum special linear group. J. Noncommut. Geom. 1 (2007), no. 3, 281309 Zbl 1137.16015 MR 2314098
, Corollary 2.8].
Note that the Leibniz formula for derivations shows that Di([I|J])=δ(iI)[I|J] and that Dj([I|J])=δ(jJ)[I|J] for any quantum minor [I|J] of 𝒪q(M(k,p)). The derivations that we have just defined are not linearly independent: it is easy to check that i=1kDi=j=1pDj.
We will extend these derivations of 𝒪q(M(k,p)) to derivations Di~ and Dj~ of T=𝒪q(M(k,p))[y±1;σ]=𝒪q(G(k,n))[u]1 as follows. For each i=1,,k, set Di~(y)=y and note that by applying the Leibniz formula for derivatives to 1=yy1 we obtain Di~(y1)=y1. For each j=1,,p, set Dj~(y)=Dj~(y1)=0. These choices for the action on y are necessary to obtain Corollary 5.2.
In the next proposition, we calculate the effect of the derivations Di~ and Dj~ on quantum Plücker coordinates in 𝒪q(G(k,n)).

Proposition 5.1.

Let [I] be a quantum Plücker coordinate in 𝒪q(G(k,n)), and let 1ik and 1jnk. Then
  1. (i)
    Di~([I])=δ(k+1iI)[I],
  2. (ii)
    Dj~([I])=δ(k+jI)[I].

Proof.

Write I=IkI>k. Then, with A=(k+1)({1,,k}\Ik) and B=I>kk, we see that [I]=[A|B]y.
In case (i),
Di~([I]) =Di~([A|B]y) =Di([A|B])y+[A|B]Di(y) =δ(iA)[A|B]y[A|B]y =(δ(iA)1)[I].
Notice that A=(k+1)({1,,k}\Ik)=(k+1)({1,,k}\I). Hence, iA if and only if k+1iI. It follows that δ(iA)+δ(k+1iI)=1. Hence, δ(iA)1=δ(k+1iI), and the result follows.
In case (ii),
Dj~([I]) =Dj~([A|B]y) =Dj~([A|B])y+[A|B]Dj~(y) =Dj([A|B])y+0 =δ(jB)[I].
Note that B=I>kk. Hence, jB=I>kk if and only if k+jI, and the result follows.  

Corollary 5.2.

We have
  1. (i)
    Di~=Dk+1i~ for 1ik,
  2. (ii)
    Dj~=Dk+j~ for 1jnk.

Example 5.3.

For 𝒪q(G(2,4)), we have D1~=D2~, D2~=D1~ and D1~=D3~, D2~=D4~.

Remark 5.4.

Note, for later use, that
(D1~++Dk~+Dk+1~++Dk+p~)|𝒪q(M(k,p))   =Dk+1++Dk+p(Dk++D1)=0,
while (D1~++Dk~+Dk+1~++Dk+p~)(y)=ky.

6. Adjusting derivatives

In cohomology calculations, we can adjust our original derivation by adding or subtracting derivations that arise as inner derivations. In this section, we consider what can happen when we do this or when adjusting by column derivations.
Let [u]=[1,,k] and [w]=[nk+1,,n] denote the leftmost and rightmost quantum Plücker coordinates of 𝒪q(G(k,n)), respectively. For any quantum Plücker coordinate [I], set d(I):=#(I\(Iu)) and e(I):=#(I\(Iw)). This notation is fixed for the rest of the paper. We will use the commutation relations for [u] and [w] with other quantum Plücker coordinates that are described in the following lemma without comment throughout the paper.

Lemma 6.1.

We have
  1. (i)
    [u][I]=qd(I)[I][u],
  2. (ii)
    [w][I]=qe(I)[I][w].

Proof.

(i) is proved in [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Lemma 3.1] and (ii) is proved in [2
A. C. Kelly, T. H. Lenagan, and L. Rigal, Ring theoretic properties of quantum grassmannians. J. Algebra Appl. 3 (2004), 930 Zbl 1081.16048 MR 2047633
, Lemma 1.5].  
If S=[I1][Im] is a standard monomial, then set d(S):=d(Ii) and note that each d(Ii)0 with d(Ii)=0 if and only if [Ii]=[u]. Then, S[u]=qd(S)[u]S, and so Su=uS if and only if d(S)=0 (in which case S=[u]m).
In any case, note that [u]S is a standard monomial, as [u] is the unique minimal quantum Plücker coordinate.
Recall from Section 2 that 𝒪q(G(k,n)) is a graded algebra with each quantum Plücker coordinate having degree one.

Lemma 6.2.

Let D be a derivation of 𝒪q(G(k,n)). Suppose that D([I])=b0++bt is the homogeneous decomposition of D([I]). Then b0=0.

Proof.

Suppose that [I][u], and suppose that D([u])=a0++as is the homogeneous decomposition of D([u]). Let d=d([I]) and note that d>0 so that qd1. By applying D to the equation [u][I]=qd[I][u], we obtain
D([u])[I]+[u]D([I])=qdD([I])[u]+qd[I]D([u]).
Examination of the terms in degree one in this equation reveals that
a0[I]+b0[u]=qdb0[u]+qda0[I],
from which it follows that a0=qda0 and b0=qdb0. Then a0=b0=0, as qd1.  
The following lemma is deduced from results in [5
S. Launois, T. H. Lenagan, and B. M. Nolan, Total positivity is a quantum phenomenon: the grassmannian case. Mem. Amer. Math. Soc. 291 (2023), no. 1448, 109 pp. Zbl 1548.16002 MR 4665212
]. In the proof of the lemma, we use the notation developed in that paper without further explanation.

Lemma 6.3.

Let v={1,,k1,k+1}, and let [α]>[v] in the standard order on quantum Plücker coordinates. Set t:=|α\(vα)| and note that t>0. Then [v][α]=qt[α][v] modulo u.

Proof.

There is an isomorphism
Ψ:𝒪q(G(k,n))u[[v]1]𝒪q1(Yλ)[Y±1;σ],
where σ(xij)=qxij for the generators xij of the partition subalgebra Yλ; see [5
S. Launois, T. H. Lenagan, and B. M. Nolan, Total positivity is a quantum phenomenon: the grassmannian case. Mem. Amer. Math. Soc. 291 (2023), no. 1448, 109 pp. Zbl 1548.16002 MR 4665212
, Theorem 9.17]. If [I|J]q1 is a t×t pseudo-quantum minor in Yλ, then we have the following commutation relation: Y[I|J]q1=qt[I|J]q1Y.
Let αΠ\{u,v}, and set t:=|α\v|. Then
Ψ(α¯v¯1)=β[I|J]q1
for some βK, and t×t pseudo-quantum minor [I|J]q1, by [5
S. Launois, T. H. Lenagan, and B. M. Nolan, Total positivity is a quantum phenomenon: the grassmannian case. Mem. Amer. Math. Soc. 291 (2023), no. 1448, 109 pp. Zbl 1548.16002 MR 4665212
, Theorem 9.17].
Hence,
Ψ(v¯α¯) =Ψ(v¯)Ψ(α¯v¯1)Ψ(v¯) =Yβ[I|J]q1Y =qtβ[I|J]q1Y2 =qtΨ(α¯v¯1)Ψ(v¯2) =qtΨ(α¯v¯),
and so v¯α¯=qtα¯v¯, as required.  

Definition 6.4.

Suppose that a=i=1saiSi is an expression for an element a𝒪q(G(k,n)) in terms of standard monomials Si and that each ai is nonzero. Then the support of a, written Supp(a), is defined to be {Si|i=1,,s}.

Lemma 6.5.

Let D be a derivation on 𝒪q(G(k,n)). Then
  1. (i)
    there are no standard monomials of the form [I1]a1[I2]a2[Im]am, with I1u and ai>0, occurring in Supp(D[u]),
  2. (ii)
    there are no standard monomials of the form [I1]a1[I2]a2[Im]am, with Imw and ai>0, occurring in Supp(D[w]).

Proof.

(i) The proof is by contradiction, so suppose that such a standard monomial exists. Without loss of generality, we may assume that I1=v={1,,k1,k+1} as we are allowing the possibility that some ai=0. As u and v differ only in one value, we know that [u][v]=q[v][u].
Apply D to the equation [u][v]=q[v][u] to obtain
D([u])[v]+[u]D([v])=qD([v])[u]+q[v]D([u]).
Suppose that D([u])=iαiSi+iαiSi where αiK and the Si,Si are standard monomials such that [u] does not occur in the Si, but does occur in the Si. Also, suppose that D([v])=jβjTj where βjK and the Ti are standard monomials. Then
iαiSi[v]+iαiSi[v]+jβj[u]Tj   =jqβjTj[u]+iqαi[v]Si+iqαi[v]Si.
Now, Si[v]=qti[v]Si modulo u for some ti0, by Lemma 6.3 (we allow zero as it might be that Si is a power of [v]).
The image of the above equation in 𝒪q(G(k,n))/[u] gives
iqtiαi[v]¯Si¯=iqαi[v]¯Si¯
or
i(qtiq)αi[v]¯Si¯=0.
Now, 𝒪q(G(k,n))/[u] is the quantum Schubert variety determined by the quantum Plücker coordinate [v] (see [6] for the definition of quantum Schubert varieties of the quantum grassmannian). As such, 𝒪q(G(k,n))/[u] has a basis consisting of the images of the standard monomials in 𝒪q(G(k,n)) that do not involve [u]; see [6, Example 2.1.3]. Consequently, each (qtiq)αi in the equation above is equal to zero. As at least one αi is nonzero, this gives qtiq=0, for that i, which is a contradiction as q is not a root of unity and ti0.
(ii) Follows in a similar fashion.  
The next corollary follows immediately from the previous lemma.

Corollary 6.6.

Let D be a derivation of 𝒪q(G(k,n)). Suppose that the homogeneous decomposition of D([u]) is given by D([u])=a1++as and that D([w])=b1++bt is the homogeneous decomposition of D([w]). Then a1 is a scalar multiple of [u] and b1 is a scalar multiple of [w].
In order to prove Conjecture 3.3, we will start by showing that we can adjust an arbitrary derivation D by adding or subtracting derivations coming from the derivations mentioned in the conjecture (column derivations and inner derivations), so that the adjusted derivation, which we will continue to denote by D, satisfies D([u])=D([w])=0. This will enable us to transfer the study of D into a quantum matrix problem by using the dehomogenisation equality. We show that we can make this adjustment in a number of steps that demonstrate how to remove standard monomials that occur in D([u]) (and D([w])).
As a result of Lemma 6.5, any standard monomial that occurs in the support of D([u]) must start with [u]. Similarly, any standard monomial that occurs in the support of D([w]) must finish with [w].
The next lemma shows that, by adjusting D by suitable inner derivations, we can remove terms of D([u]) that are not of the form α[u]a for values of a1.

Lemma 6.7.

Suppose that S=[u]a[I1]b1[I2]b2[Im]bm is a standard monomial with [v][I1] and ibi>0, while a1. Let D be a derivation of 𝒪q(G(k,n)), and suppose that S occurs in the support of D([u]) with nonzero scalar coefficient α. Set d:=d(S)=b1d(I1)++bmd(Im), and set z:=αqd1[u]a1[I1]b1[I2]b2[Im]bm. Also, set D:=Dadz. Then
Supp(D([u]))=Supp(D([u]))\{S}.

Proof.

Note that d>0, so qd10. We calculate
adz([u]) =zuuz =αqd1([u]a1[I1]b1[I2]b2[Im]bm[u][u]a[I1]b1[I2]b2[Im]bm) =αqd1(qd[u]a[I1]b1[I2]b2[Im]bm[u]a[I1]b1[I2]b2[Im]bm) =αqd1((qd1)[u]a[I1]b1[I2]b2[Im]bm) =αS.
It follows that Supp(D([u]))=Supp(D([u]))\{S}, as required.  

Corollary 6.8.

Let D be a derivation of 𝒪q(G(k,n)). Then there is a derivation D such that DD is a sum of inner derivations and such that the homogeneous terms of D([u]) are of the form λa[u]a for a1 and λaK.

Proof.

Lemma 6.5 shows that Supp(D([u])) has no terms whose standard monomials do not begin with [u]. By using Lemma 6.7 an appropriate number of times, we can remove terms in Supp(D([u])) that involve [u] and at least one other quantum Plücker coordinate by adjusting with suitable inner derivations. What remains is a derivation D whose support only involves terms of the form [u]a.  
Our next task is to show that we can adjust further, if necessary, to see that we can reduce to a=1 being the only possibility.

Lemma 6.9.

Suppose that D is a derivation of 𝒪q(G(k,n)) such that [u]a1[w] occurs in Supp(D([w])) with a>1. Then there is a derivation D of 𝒪q(G(k,n)) such that DD is inner and D([u])=D([u]) while Supp(D([w]))=Supp(D([w]))\[u]a1[w].

Proof.

Suppose that [u]a1[w] occurs in Supp(D([w])), say with nonzero coefficient β. Now, ad[u]a1([w])=[u]a1[w][w][u]a1=(1qd(w)(a1))[u]a1[w], and note that 1qd(w)(a1)0, as both d(w) and a1 are nonzero and q is not a root of unity. Set D:=Dβ(1qd(w)(a1))1ad[u]a1. Then D([u])=D([u]), as ad[u]a1([u])=0. Also, D([w])=D([w])β(1qd(w)(a1))1ad[u]a1([w])=D([w])β[u]a1[w], so that Supp(D([w]))=Supp(D([w]))\[u]a1[w], as required.  
The following corollary now follows by applying the previous lemma an appropriate number of times.

Corollary 6.10.

Let D be a derivation of 𝒪q(G(k,n)). Then there is a derivation D of 𝒪q(G(k,n)) such that DD is a sum of inner derivations, D([u])=D([u]) and such that there are no terms of the form [u]a1[w] with a>1 occurring in Supp(D([w])).

Lemma 6.11.

Let D be a derivation of 𝒪q(G(k,n)) such that D([u])=λi[u]i for some λiK, and suppose that no terms of the form [u]a1[w] with a>1 occur in Supp(D([w])). Then D([u])=λ1[u].

Proof.

Suppose that D([w])=βiSi for some standard monomials Si and 0βiK, and note that there is no Si such that Si=[u]a1[w] for any a>1, by assumption. Apply D to the equation [u][w]=qd(w)[w][u] to obtain
D([u])[w]+[u]D([w])=qd(w)D([w])[u]+qd(w)[w]D([u]).
Hence,
λi[u]i[w]+βi[u]Si=qd(w)βiSi[u]+qd(w)λi[w][u]i
and so
λi[u]i[w]+βi[u]Si=qd(w)d(Si)βi[u]Si+qd(w)id(w)λi[u]i[w].
The terms in this equation are all scalar multiples of standard monomials. Consider the occurrences of the standard monomial [u]a[w] for a given a>1. If [u]Si=[u]a[w], then Si=[u]a1[w], which does not occur, by assumption. Hence, the second term on the left side of this equation and the first term on the right side do not contain [u]a[w]. It follows that λa[u]a[w]=q(1a)d(w)λa[u]a[w], and this forces λa(1q(1a)d(w))=0. Now, (1a)d(w)0, as a1 so (1q(1a)d(w))0. Hence, λa=0. As this is true for all a>1, we obtain the required result.  
Recall from Lemma 3.1 that the column derivation D1 is acting on a quantum Plücker coordinate [I] by D1([I])=δ(1I)[I].

Corollary 6.12.

Let D be a derivation of 𝒪q(G(k,n)) such that D([u])=λ[u] for some λK, and suppose that no terms of the form [u]a1[w] with a>1 occur in Supp(D([w])). Then there is a derivation D of D such that the following hold:
  1. (i)
    D([u])=0.
  2. (ii)
    DD=λD1.
  3. (iii)
    There are no terms of the form [u]a1[w] with a>1 that occur in Supp(D([w])).

Proof.

We start by observing that D1([u])=D1([1,,k])=[u] and D1([w])=D1([nk+1,,n])=0, as 1<nk+1. Set D=DλD1, so that D([u])=D([u])λD1([u])=λ[u]λ[u]=0. Also, D([w])=D([w])λD1([w])=D([w]), so no terms of the form [u]a1[w] with a>1 occur in Supp(D([w])).  

Lemma 6.13.

Let D be a derivation of 𝒪q(G(k,n)) with the following properties:
  1. (i)
    D([u])=0.
  2. (ii)
    Supp(D([w])) contains no term of the form [u]a1[w] for a>1.
Then D([w])=α[w] for some αK.

Proof.

Recall, from Lemma 6.5, that [w] must occur in any standard monomial contained in Supp(D([w])). Suppose that S=[u]a[I1]a1[Im]am[w]bSupp(D([w])) with u<I1 and Im<w, while a,ai0,b>0. Suppose that S occurs in D([w]) with nonzero coefficient αK. Note that d(Ii)>0 for each i. Apply D to the equation [u][w]=qd(w)[w][u], remembering that D([u])=0, to obtain
[u]D([w])=qd(w)D([w])[u].
Examination of the standard monomials of the form [u]S in this equation reveals that
α[u]a+1[I1]a1[Im]am[w]b   =αqd(w)[u]a[I1]a1[Im]am[w]b[u]   =αqd(w)(d(w)b+a1d(I1)++amd(Im))[u]a+1[I1]a1[Im]am[w]b.
As q is not a root of unity, the only possibility is that the power of q on the right-hand side is q0, and this is only possible for b=1 and a1==am=0. Thus, the only possible terms in Supp(D[w]) are of the form [u]a[w]. Taking into account condition (ii) in the statement of the lemma, we see that a>0 is not allowed, so D[w]=α[w], as required.  
Recall from Lemma 3.1 that there are column derivations Di for i=1,,n such that Di([I])=δ(iI)[I] for each quantum Plücker coordinate [I]. The results of this section are summarised in the following proposition.

Proposition 6.14.

Let D be a derivation of 𝒪q(G(k,n)). Then there is a derivation D of 𝒪q(G(k,n)) with D([u])=D([w])=0 and such that (DD) is a linear combination of derivations of the form adz, with z𝒪q(G(k,n)), and column derivations Di for i=1,,n.

Proof.

We know the following facts hold for any derivation D of 𝒪q(G(k,n)) and so will hold for the any derivation that occurs when we adjust a given derivation by adding or subtracting inner derivations and scalar multiples of the Di: (i) the degree zero parts of D([u]) and D([w]) are both zero (see Lemma 6.2); (ii) the degree one part of D([u]) is a scalar multiple of [u] and, similarly, the degree one part of D([w]) is a scalar multiple of [w] (see Corollary 6.6); (iii) any standard monomial occurring in the support of D([u]) must start with at least one occurrence of [u] and, similarly, any standard monomial occurring in the support of D([w]) must end with at least one occurrence of [w] (see Lemma 6.5).
Let D be an arbitrary derivation of 𝒪q(G(k,n)). By Corollary 6.8, there is a derivation D(1) of 𝒪q(G(k,n)) such that D(1)D is a sum of inner derivations and such that the homogeneous terms of D(1)([u]) are of the form λa[u]a for a1 and αaK.
By Corollary 6.10, there is a derivation D(2) of 𝒪q(G(k,n)) such that D(2)D(1) is a sum of inner derivations; the homogeneous terms of D(2)([u])=D(1)([u]) are of the form λa[u]a for a1 and αaK, and there are no terms of the form [u]a1[w] with a>1 occurring in Supp(D(2)([w])). By Lemma 6.11, D(2)([u])=λ[u] for some λK.
Set D(3):=D(2)λD1. Then D(3)([u])=0, while
D(3)([w])=D(2)([w])λD1([w])=D(2)([w]),
as D1([w])=0. Hence, there are no terms of the form [u]a1[w] with a>1 in D(3)([w]). It follows from Lemma 6.13 that D(3)([w])=α[w] for some αK.
Finally, set D:=D(3)αDn. Then D([u])=D(3)[u]=0, as Dn([u])=0 and D([w])=D(3)([w])αDn([w])=0. The passage from D to D via D(1),D(2),D(3) only involves adjustments by adding or subtracting derivations of the form adz, with z𝒪q(G(k,n)), and Di for i=1,,n at each stage, so the required result follows.  

7. Transferring derivations of 𝒪q(G(k,n)) to 𝒪q(M(k,p))

Throughout this section, we assume that 2kn.
Recall the dehomogenisation equality from Section 4
T=𝒪q(G(k,n))[[u]1]=𝒪q(M(k,p))[y,y1;σ].
Given a derivation D of 𝒪q(G(k,n)) with D([u])=D([w])=0, we may extend D to T by setting D([u]1)=0 and then transfer to 𝒪q(M(k,p))[y,y1;σ] via the dehomogenisation equality. We then know that D(y)=D([u])=0. We retain the notation D for this extension to T.
Recall that in Section 4 we set R:=𝒪q(M(k,p)) where p=nk. The quantum matrix generators xij of R are defined in Section 4
xij:=[1,,k+1i^,,k,j+k][u]1T.
Our aim in this section is to show that D(R)R for such a derivation D. We will use a pair of gradings of T that were developed in [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Section 6] to discuss a similar result for certain automorphisms of 𝒪q(G(k,n)).
As 2kn, we know that knk=p, and so R has at least k columns and the quantum minor [I|J]:=[1k|p+1k,,p]R is defined (we are using all the rows of R=𝒪q(M(k,p)) and the last k columns). As noted in [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Lemma 6.1], xij[I|J]=q[I|J]xij when j<p+1k while xij[I|J]=[I|J]xij when jp+1k. As a consequence, [I|J] is a normal element in R and also in T.

Lemma 7.1.

Let D be a derivation of 𝒪q(G(k,n)), where 2kn, with D([u])=D([w])=0. Let [I|J] be defined as in the previous paragraph. Then D([I|J])=0.

Proof.

The discussion at the end of Section 4 shows that
[I|J]=[p+1n][1k]1=[w][u]1,
and so D([I|J])=D([w][u]1)=0.  
Also, we can calculate how [I|J] commutes with [u]=[1k]. Note that k<nk+1=p+1, as 2kn. Thus, the index sets {1,,k} and {p+1,,n} do not overlap, and
[u][I|J]=[u][w][u]1=qk[w][u][u]1=qk[w][u]1[u]=qk[I|J][u],
where the second equality comes from Lemma 6.1.
The two gradings that were used in [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Section 6] are defined by considering how elements of T commute with y=[u] and with [I|J].
We set Ti:={aT|yay1=qia} and T(i):={aT|[I|J]a[I|J]1=qia}.

Lemma 7.2.

We have
  1. (i)
    T=i=1Ti,
  2. (ii)
    T=i=T(i),
  3. (iii)
    (T(0)T(1))T1𝒪q(M(k,p))=R.

Proof.

These results are established in [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Lemmas 6.2 (i), 6.3 (i) and 6.4].  

Theorem 7.3.

Suppose that 2kn and that D is a derivation of 𝒪q(G(k,n)) such that D([u])=D([w])=0. Then D(R)R.

Proof.

It is enough to show that D(xij)R for each generator xij of R.
Note that xij(T(0)T(1))T1. This claim follows from the commutation rules given in [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Lemma 6.1] and the fact that yxij=qxijy.
Let aT1. Then ya=qay. Apply D to this equation, noting that D(y)=0, to obtain yD(a)=qD(a)y, so that D(T1)T1. Similar calculations, using the fact that D([I|J])=0 show that D(T(0))T(0) and D(T(1))T(1). It follows that D(xij)D((T(0)T(1))T1)(T(0)T(1))T1R.
As D takes each generator xij of R into R, we see that D(R)R, as required.  

8. The main theorem

Recall that we are assuming that K is a field of characteristic zero and that qK is a nonzero element that is not a root of unity. We are also assuming that k1, as in this case the quantum grassmannian is a quantum affine space, where the results are known; see [1
J. Alev and M. Chamarie, Dérivations et automorphismes de quelques algèbres quantiques. Comm. Algebra 20 (1992), no. 6, 17871802 Zbl 0760.17003 MR 1162608
]. As 𝒪q(G(n1,n))𝒪q(G(1,n)), we exclude this case as well. Thus, we are assuming that 2kn2.
In this section, we prove Conjecture 3.3. The proof proceeds by first analysing the case where 2kn. The general case is then obtained by using the isomorphism 𝒪q(G(k,n))𝒪q(G(nk,n)). In order to avoid breaking the flow of the main result, we relegate to the appendix a discussion concerning homogeneous derivations on non-square quantum matrices that we use in obtaining the truth of the conjecture in the case where 2k<n.
In this section, in order to make reading easier, we will use δ to denote an arbitrary derivative.

8.1. The case where 2kn

In this subsection, we consider 𝒪q(G(k,n)) in the case that 2kn. In this case, the dehomogenisation equality is
𝒪q(G(k,n))[[u]1]=T=𝒪q(M(k,p))[y,y1;σ],
where p=nk. We set R:=𝒪q(M(k,p)).
When 2k=n, so that R=𝒪q(M(k,k)), it is well known that the centre of R is K[Dq], where Dq is the quantum determinant of 𝒪q(M(k,k)). It is also well known that when 2k<n, so that R is non-square, the centre of R is K. We also recall that the centre of 𝒪q(G(k,n)) is always reduced to scalars. This follows easily from the basis of standard monomials by first observing that an element is central in 𝒪q(G(k,n)) if and only if all the standard monomials in its support are central, and next by noting that there are no non-trivial central standard monomials since the only standard monomial commuting with both [u] and [w] are scalars by Lemma 6.1.

Proposition 8.1.

Assume that 2kn. Then any derivation δ of 𝒪q(G(k,n)) is equal, modulo inner derivations, to a linear combination of D1,,Dn. Furthermore, these n derivations are linearly independent modulo the inner derivations.

Proof.

We use the same notation δ for the extension to T. After possibly adjusting δ by inner derivations and linear combinations of D1,,Dn, we may assume that δ(y)=δ([u])=δ([w])=0, by Proposition 6.14, and then δ(R)R, by Theorem 7.3. Apply δ to the equation yxij=qxijy to obtain
yδ(xij)=qδ(xij)y.
Given this equation and the fact that δ(R)R, we conclude that δ(xij) is homogeneous of degree one.
In order to prove the first claim, we consider the two cases (i) 2k=n and (ii) 2k<n separately in order to show the subclaim that δ|R can be written as a linear combination of the row and column derivations Di,Dj of the quantum matrix algebra R introduced in Section 5.

Subclaim: Case (i)

First, suppose that 2k=n, so that k=nk. In this case, R=𝒪q(M(k,k)), and so R is a square quantum matrix algebra and the centre of R is K[Dq], where Dq is the quantum determinant of 𝒪q(M(k,k)).
By [3
S. Launois and T. H. Lenagan, The first Hochschild cohomology group of quantum matrices and the quantum special linear group. J. Noncommut. Geom. 1 (2007), no. 3, 281309 Zbl 1137.16015 MR 2314098
, Theorem 2.9], there are polynomials P1,,Pk,Q1,,QkK[Dq] and an element zR such that
δ|R=adz+i=1kPiDi+j=1nkQjDj,
where Di,Dj are the row and column derivations of R introduced in Section 5.
Let ai be the constant term in Pi and bj be the constant term in Qj. Then
δ(xrs)(i=1kaiDi(xrs)+j=1nkbjDj(xrs))   =zxrsxrsz+i=1k(Piai)Di(xrs)+j=1nk(Qjbj)Dj(xrs)
for all r,s. The terms on the left-hand side of this equation all have degree one, whereas the terms on the right-hand side have degree greater than one, because zxrsxrsz has no degree zero or degree one terms.
It follows that both sides are zero, and so δ|R=i=1kaiDi+j=1nkbjDj, which establishes the subclaim in the case that 2k=n.

Subclaim: Case (ii)

Next, suppose that 2k<n. In this case, R=𝒪q(M(k,p)), where p=nk>k and so R is a non-square quantum matrix algebra with more columns than rows, and the centre of R is K. The proof of this case is substantially more complicated than that of case (i) due to the fact that [3
S. Launois and T. H. Lenagan, The first Hochschild cohomology group of quantum matrices and the quantum special linear group. J. Noncommut. Geom. 1 (2007), no. 3, 281309 Zbl 1137.16015 MR 2314098
, Theorem 2.9] only covers derivations for square quantum matrices. To avoid disturbing the flow of the proof of this proposition, the proof of this subclaim is treated in the appendix and finally established in Proposition A.6.
Having established the subclaim, we revert to the condition that 2kn.
By using Corollary 5.2, we see that
δ|R=i=1kaiDi+j=1nkbjDj=(i=1kaiDi~+j=1nkbjDk+j~)|R.
We define δ~=i=1kaiDi~+j=1nkbjDk+j~, so that δ|R=δ~|R. Note that δ~(y)=(i=1kai)y, as Di~(y)=y for i=1,,k, while Dk+j~(y)=0 for j=1,,nk. Recall from Remark 5.4 that i=1nDi~ acts trivially on R, while i=1nDi~(y)=ky.
Set δ^:=(1ki=1kai)(i=1nDi~). Then, for all r and s, we have (δ~+δ^)(xrs)=δ~(xrs)+δ^(xrs)=δ~(xrs)+0=δ(xrs), while (δ~+δ^)(y)=δ~(y)+δ^(y)=(ai)y+(1kai)(ky)=0=δ(y). As δ and δ~+δ^ agree on the generating set xij,y, they are equal as derivatives.
For the proof of the second part, suppose that
adz+i=1naiDi=0
for some z𝒪q(G(k,n)) and aiK. Thus, adz([I])+i=1naiδ(iI)[I]=0 for each quantum Plücker coordinate [I]𝒪q(G(k,n)). The first term has no components in degree one and the other terms are all in degree one, so we deduce that adz([I])=0 for each quantum Plücker coordinate [I]𝒪q(G(k,n)), so that adz=0. Thus, we obtain i=1naiDi=0.
For r=1,,n+1k, set [Ir]:=[1,,k1,k1+r], and observe that
0=i=1naiDi[Ir]=((a1++ak1)+ak1+r)[Ir].
Thus, (a1++ak1)+ak1+r=0 for each of these values of r. It follows that ak=ak+1==an. In a similar manner, set [Jr]:=[nk+1r,nk+2,,n] for r=0,,nk to observe that ank+1r+(ank+2++an)=0 for these values of r. It follows that a1==ank+1. These two ranges of values must overlap, or else nk+1<k, so that n+1<2kn, a contradiction. Thus, a1=a2==an, and from this and Corollary 3.2, it follows that each ai=0.  

8.2. The general case

We have now proved our conjecture for 𝒪q(G(k,n)) in the case where 2kn. In order to remove this restriction, we use the fact that 𝒪q(G(k,n))𝒪q(G(nk,n)); see, for example, [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Proposition 3.1]. We will use D¯ to distinguish derivations of 𝒪q(G(nk,n)) from derivations of 𝒪q(G(k,n)). Let ψ:𝒪q(G(k,n))𝒪q(G(nk,n)) be the automorphism of [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Proposition 3.1], so that ψ([I])=[w0(I^)] for each quantum Plücker coordinate [I] of 𝒪q(G(k,n)), where I^:={1,,n}\I and w0 is the longest element of the symmetric group Sn. Let D be a derivation of 𝒪q(G(k,n)). It is easy to check that ψDψ1 is a derivation of 𝒪q(G(nk,n)). Similarly, if D¯ is a derivation of 𝒪q(G(nk,n)), then ψ1D¯ψ is a derivation of 𝒪q(G(k,n)).
Recall that we have the derivations Di of 𝒪q(G(k,n)) for i=1,,n, with Di([I])=δ(iI)[I], and similarly we have derivations Dj¯ of 𝒪q(G(nk,n)) for j=1,,n.
For each i, we need to see how ψDiψ1 acts as a derivation on 𝒪q(G(nk,n)) in terms of the Dj¯.
Note from Corollary 3.2 that 1nk(j=1nDj¯)([J])=[J] for each quantum Plücker coordinate [J]𝒪q(G(nk,n)).

Lemma 8.2.

We have
ψDiψ1=1nk(j=1nDj¯)D¯w0(i).

Proof.

Let [J] be a quantum Plücker coordinate in 𝒪q(G(nk,n)) and suppose that [J]=ψ([I])=[w0(I^)] for a quantum Plücker coordinate [I] of 𝒪q(G(k,n)).
Before we do the calculation of ψDiψ1, note the following evaluation of a truth function:
δ(iI)=1δ(iI^)=1δ(w0(i)w0(I^))=1δ(w0(i)J).
We obtain
ψDiψ1([J]) =ψDi([I])=ψ(δ(iI)[I])=δ(iI)[J] =(1δ(w0(i)J))[J]=[J]D¯w0(i)([J]) ={1nk(j=1nDj¯)D¯w0(i)}([J]),
as required.  
We can now obtain our main theorem without any restriction other than 1<k<n1. Given that we have proved the conjecture in the case that 2kn, it is enough to prove the result for 𝒪q(G(nk,n)) when 2kn.

Proposition 8.3.

Assume that 2kn. In 𝒪q(G(nk,n)) any derivation is equal, modulo inner derivations, to a linear combination of D1¯,,Dn¯. Furthermore, these n derivations are linearly independent modulo the inner derivations.

Proof.

Let D¯ be a derivation on 𝒪q(G(nk,n)). Then ψ1D¯ψ is a derivation of the algebra 𝒪q(G(k,n)). Hence,
ψ1D¯ψ=adz+i=1naiDi
for some z𝒪q(G(k,n)) and aiK, by Proposition 8.1.
Therefore,
D¯=adψ(z)+i=1naiψDiψ1=adψ(z)+i=1nai{1nk(j=1nDj¯)D¯w0(i)},
and the first claim follows.
The proof of the second part follows in the same way as for the second part of Proposition 8.1.  
We are now ready to state and prove our main result.

Theorem 8.4.

Let 2kn2. Then any derivation of 𝒪q(G(k,n)) is equal, modulo inner derivations, to a linear combination of D1,,Dn. Furthermore, these n derivations are linearly independent modulo the inner derivations.

Proof.

The result in the case that 2kn has been established in Proposition 8.1, so suppose that 2k>n. Set k:=nk, then 2k<n and nk=k. As 2k<n, the result holds for 𝒪q(G(k,n)). It then follows that the result holds for 𝒪q(G(k,n))=𝒪q(G(nk,n)), by using Proposition 8.3.  
Recall that the Hochschild cohomology group in degree one of a ring R, denoted by HH1(R), is defined by
HH1(R):=Der(R)/InnDer(R),
where InnDer(R):={adz|zR} is the Lie algebra of inner derivations of R. It is well known that HH1(R) is a module over HH0(R):=Z(R).
The following corollary is immediate from the above theorem.

Corollary 8.5.

Let 2kn2. The first Hochschild cohomology group of the quantum grassmannian, HH1(𝒪q(G(k,n))), is an n-dimensional vector space over K with basis (the cosets of) D1,,Dn.

A. Derivations on non-square quantum matrices

In this appendix, we prove case (ii) of the subclaim in the proof of Proposition 8.1. To be more specific, in case (ii) of the subclaim, we are dealing with a derivation of 𝒪q(M(k,p)), where k<p, that arises, via the dehomogenisation equality, from a derivation D of 𝒪q(G(k,n)) that has the following properties: (i) D([u])=D([w])=0; (ii) D is a homogeneous derivative of 𝒪q(M(k,p)). As a consequence of Lemma 7.1, the first condition implies that the derivative D acts trivially on the rightmost quantum minor of 𝒪q(M(k,p)).
Hence, with a change of notation, throughout this appendix, we assume that we are considering derivations on 𝒪q(M(m,n)) where m<n and that we have a derivation D acting on 𝒪q(M(m,n)) with the following properties:
  1. (i)
    The derivation D is homogeneous; that is, all terms appearing non-trivially in D(xrs) have degree one.
  2. (ii)
    D([1,,m|n+1m,,n])=0.
The aim in this appendix is to show that such a derivation can be written as a linear combination of the row and column derivations Di and Dj that were introduced in Section 5. With this in mind, we fix the following notation.

Notation A.1.

Throughout the appendix, B denotes the quantum matrix subalgebra of 𝒪q(M(m,n)) generated by xrs in the first nm columns of 𝒪q(M(m,n)) and C denotes the square quantum matrix subalgebra of 𝒪q(M(m,n)) generated by the xrs in the final m columns. The quantum determinant of C is [I|J]:=[1,,m|nm+1,,n] and [I|J] is in the centre of C.

A.1. Action of derivations on first m columns of 𝒪q(M(m,n))

Lemma A.2.

Use Notation A.1. Let D be a derivation on 𝒪q(M(m,n)) such that D(xij) is homogeneous of degree one for all xij, and suppose that D([I|J])=0. Then D(B)B.

Proof.

It is enough to show that D(xij)B for jm. For such an xij, suppose that
D(xij)=rmsnarsxrs
with arsK. Now, xij[I|J]=q[I|J]xij, by [4
S. Launois and T. H. Lenagan, The automorphism group of the quantum grassmannian. Bull. Lond. Math. Soc. 56 (2024), no. 4, 13101327 Zbl 1554.16033 MR 4736773
, Lemma 6.1 (ii)]. Apply D to this equation, noting that D([I|J])=0, to obtain
1rm1snarsxrs[I|J]=q[I|J]1rm1snarsxrs.
As xrs[I|J]=q[I|J]xrs when sm, and xrs[I|J]=[I|J]xrs for s>m, this gives
rms>m(1q)arsxrs[I|J]=0,
and it follows that ars=0 when s>m, so that D(xij)B, as required.  

A.2. We can adjust D, so that D is trivial on C

Lemma A.3.

Use Notation A.1. Let D be a derivation on 𝒪q(M(m,n)) such that D(xik) is homogeneous of degree one for all xik, and suppose that D([I|J])=0. Then D(C)C.

Proof.

This is proved in a similar manner to the proof of Lemma A.2, using the fact that xik commutes with [I|J] for xik in C.  
We now show that we can adjust D by row and column derivations, so that the adjusted derivation acts trivially on C.

Lemma A.4.

Use Notation A.1. Let D be a derivation on 𝒪q(M(m,n)) such that D(xrs) is homogeneous of degree one for all xrs, and suppose that D([I|J])=0. There is a homogeneous derivation D of 𝒪q(M(m,n)) with D|C=0 and D(B)B such that DD is a linear combination of Di, for i=1,,m, and Dj, for nm+1jn, the row and column derivations of 𝒪q(M(m,n)) introduced in Section 5.

Proof.

Note that D(C)C, by Lemma A.3. Set Y:=[I|J], the quantum determinant of C. By [3
S. Launois and T. H. Lenagan, The first Hochschild cohomology group of quantum matrices and the quantum special linear group. J. Noncommut. Geom. 1 (2007), no. 3, 281309 Zbl 1137.16015 MR 2314098
, Theorem 2.9], there are polynomials P1,,Pm,Qnm+1,,QnK[Y] and an element zC such that
D|C=adz+i=1mPiDi|C+j=nm+1nQjDj|C.
Let snm+1, so that xrsC. Then
D|C(xrs)=adz(xrs)+i=1mPiDi|C(xrs)+j=nm+1nQjDj|C(xrs).
Let ai be the constant term in Pi and bj be the constant term in Qj, so that
D|C(xrs)i=1maiDi|C(xrs)+j=nm+1nbjDj|C(xrs)   =zxrsxrsz+i=1m(Piai)Di|C(xrs)+j=nm+1n(Qjbj)Dj|C(xrs).
As D(xrs) is homogeneous of degree one, the terms on the left-hand side of the equation all have degree one, whereas the nonzero terms on the right-hand side all have degree greater than one. It follows that both sides are zero, and so
D|C(xrs)=i=1maiDi|C(xrs)+i=nm+1nbjDj|C(xrs).
Set
D:=Di=1maiDi+i=nm+1nbjDj.
Then D|C=0. Note that D is a homogeneous derivation as D, Di and Dj are all homogeneous. Lemma A.2 shows that D(B)B.  

A.3. Derivatives column by column

Let ε1,,εm and ε1,,εn be the standard bases for m and n, respectively. The quantum matrix algebra 𝒪q(M(m,n)) has a natural m×n bigrading defined by giving each xrs bidegree, also called bicontent, (εr,εs). Observe that any quantum minor [U|V] is homogeneous of bidegree (χU,χV), where χS (respectively, χS) stands for the characteristic function of a subset S of {1,,m} (respectively, of {1,,n}). If the bidegree of a homogeneous element is (χr,χc), we refer to χr as the row content of the element and χc as the column content of the element. The main use of the notion of content will be that in any equation of the form P=Q, the terms of the same bicontent on each side of the equation must be equal.
We consider 𝒪q(M(m,n)) with m<n and assume that we have a homogeneous derivation D that acts trivially on C and that D(B)B.

Lemma A.5.

Use Notation A.1. Let D be a derivation on 𝒪q(M(m,n)) such that D(xik) is homogeneous of degree one for all xik and that D(C)=0. Then D is a linear combination of Dk for k=1,,nm.

Proof.

Let xikB, so that 1im and 1knm. As D(B)B, by Lemma A.2, we can write
D(xik)=1rm1snmars(ik)xrs
for some ars(ik)K. Our first aim is to show that ars(ik)=0 whenever ri, so that
D(xik)=1snmais(ik)xis.
Set l:=nm+1. Choose any j<i. Note that xikxjl=xjlxik. As xjlC, we know that D(xjl)=0, so that when we apply the derivative D to this equation, we obtain
1rm1s<lars(ik)xrsxjl=1rm1s<lars(ik)xjlxrs
or
1rm1s<lars(ik)(xrsxjlxjlxrs)=0.
Consider terms in this equation with bicontent (2εj;εs+εl) (which from now on we also denote by (j,j;s,l) to ease notation) to see that
1s<lajs(ik)(xjsxjlxjlxjs)=0.
As s<l, this gives
1s<lajs(ik)(q1)xjlxjs=0.
From which it follows that ajs(ik)=0 for all s when j<i.
Next, choose any j>i. As D(xjk)B, write
D(xjk)=1rm1s<lars(jk)xrs.
Apply D to the equation xikxjlxjlxik=q^xilxjk (where q^:=qq1), noting that D(xl)=0 as xlC, to obtain
(A.1)
1rm1s<lars(ik)xrsxjl1rm1s<lars(ik)xjlxrs=q^(1rm1s<lars(jk)xilxrs).
Look at terms with bicontent (j,j;s,l) in equation (A.1). There are no such terms on the right-hand side, as i occurs as a row index and ij, while on the left-hand side, we get such terms when r=j. Hence, ajs(ik)xjsxjlajs(ik)xjlxjs=0 for each s. As s<l, this gives the equality (q1)ajs(ik)xjsxjl=0 and so ajs(ik)=0 for all s and each j>i. As we already know that ajs(ik)=0 for all s when j<i, this gives
D(xik)=1s<lais(ik)xis
for 1im as required.
Fix k, with 1k<l and j>1. Apply the derivative D to the equation x1kxjlxjlx1k=q^x1lxjk, using the expressions we have just derived, to obtain
(A.2)
1s<la1s(1k)x1sxjl1s<la1s(1k)xjlx1s=q^1s<lajs(jk)x1lxjs.
Look at terms with content (1,j;s,l) in equation (A.2) for fixed s. On the left-hand side, we have a1s(1k)x1sxjla1s(1k)xjlx1s, and this is equal to q^a1s(1k)x1lxjs. On the right-hand side, we have q^ajs(jk)x1lxjs. It follows that ajs(jk)=a1s(1k) for each s with 1s<l, so that
D(xjk)=1s<la1s(1k)xjs
for each j with 1jm.
Hence,
(A.3)
D(x1kx2kxmk)=a11(1k)(x11x21xm1)+a12(1k)(x12x22xm2)++a1,l1(1k)(x1,l1x2,l1xm,l1).
For each k=1,,l1, we want to show that a1r(1k)=0 when rk, so that
D(x1kx2kxmk)=a1k(1k)(x1kx2kxmk)=a1k(1k)Dk(x1kx2kxmk).
Fix k with 1kl1. First, we show that a1r(1k)=0 for each r such that k<rl1. If k=l1, there is no such r to consider, so assume that k<l1, in which case k+1<l and x1,k+1B. Apply D to the equation x1kx1,k+1=qx1,k+1x1k for k+1<l to obtain
D(x1k)x1,k+1+x1kD(x1,k+1)=qD(x1,k+1)x1k+qx1,k+1D(x1k),
which gives
(A.4)
1s<la1s(1k)x1sx1,k+1+1s<la1s(1,k+1)x1kx1s   =1s<lqa1s(1,k+1)x1sx1k+1s<lqa1s(1k)x1,k+1x1s.
Consider terms in this equation with content (1,1;k+1,r) for r>k. These occur in the first and fourth sums when s=r and do not occur in the second and third sums because k is in the column content of the terms in these sums. Hence, a1r(1k)x1rx1,k+1=qa1r(1k)x1,k+1x1r. If r=k+1, then we get a1,k+1(1k)x1,k+1x1,k+1=qa1,k+1(1k)x1,k+1x1,k+1 and so a1,k+1(1k)=0. If r>k+1, then x1rx1,k+1=q1x1,k+1x1r. So we see that q1a1r(1k)x1,k+1x1r=qa1r(1k)x1,k+1x1r and so a1r(1k)=0. Hence, a1,r(1,k)=0 for all r>k.
Next, we show a1r(1k)=0 when r<k. If k=1, then there is no such r to consider, so assume that k>1, in which case k11, so that x1,k1 exists and is in B. Apply D to the equation x1,k1x1,k=qx1,kx1,k1 to obtain
D(x1,k1)x1,k+x1,k1D(x1,k)=qD(x1,k)x1,k1+qx1,kD(x1,k1),
which gives
(A.5)
1s<la1s(1,k1)x1sx1,k+1s<la1s(1,k)x1,k1x1s   =1s<lqa1s(1k)x1sx1,k1+1s<lqa1s(1,k1)x1kx1s.
Consider terms in this equation with content (1,1;r,k1) with r<k. There are no such terms in the first and fourth terms, as k is in the column content of the terms in these sums, and such terms occur in the second and third terms when s=r. Hence, a1r(1,k)x1,k1x1r=qa1r(1,k)x1rx1,k1.
When r=k1, we see that a1,k1(1,k)x1,k1x1,k1=qa1,k1(1,k)x1,k1x1,k1, so that a1,k1(1,k)=0.
When r<k 1, then x1,k1x1r=q1x1rx1,k1, so we see that q1a1,r(1,k)x1rx1,k1=qa1,r(1,k)x1,rx1,k1 and so a1,r(1,k)=0.
Hence, a1,r(1,k)=0 for all r<k. Thus, a1r(1k)=0 whenever rk, so that D(xik)=aik(1k)xik for each 1im, as required to show that
D(x1kx2kxmk)=a1k(1k)(x1kx2kxmk)
for each 1k<l. As we already know that D acts trivially on columns n+1m up to n, this gives
D=a11(1,1)D1+a12(1,2)D2++a1,l1(1,l1)D,l1,
as required.  

A.4. Conclusion of appendix

The preceding analysis proves the following proposition.

Proposition A.6.

Suppose that m<n and that we have a derivation D of 𝒪q(M(m,n)) such that
  1. (i)
    the derivation  D is homogeneous; that is, all terms appearing non-trivially in D(xij) have degree one,
  2. (ii)
    D([1,,m|n+1m,,n])=0.
Then
D=i=1maiDi+k=1nbkDk
for some ai,bkK.

Proof.

By Lemma A.4, there is a homogeneous derivation D(1) such that D(1)D is a linear combination of the Di, with 1im, and Dj, with nm+1jn, and such that D(1)|C=0. By Lemma A.5, D(1) is a linear combination of the Dk with 1knm. Writing D=D(1)(D(1)D) gives the required result.  

Funding

This research was partly supported by EPSRC grant EP/R009279/1.

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Cite this article

Stéphane Launois, Thomas H. Lenagan, Derivations and the first Hochschild cohomology group of the quantum grassmannian. J. Noncommut. Geom. 20 (2026), no. 3, pp. 845–870

DOI 10.4171/JNCG/662